Question

(x^2-10)^2-3(x^2-10)-4=0

Answer 1

(x²-10)²-3(x²-10)-4=0
x⁴-20x²+100-3x²+30-4=0
x⁴-23x²-126=0
Пусть x²=t
t²-23t-126=0
t₁=9
t₂=14
x²=9
x=3;-3
x²=14
x=√14;-√14
Ответ:3;-3;√14;-√14