Question

решите задания во вкладках.........

Answer 1

$frac{1}{3} (2 sqrt{150} +3 sqrt{24} -5 sqrt{54} )^2+15cdot sqrt[4]{625} = \ = frac{1}{3} (2 sqrt{25cdot6} +3 sqrt{4cdot6} -5 sqrt{9cdot6} )^2+15cdot sqrt[4]{5^4} = \ = frac{1}{3} (10 sqrt{6} +6 sqrt{6} -15 sqrt{6} )^2+15cdot 5 = frac{1}{3} (sqrt{6})^2+75= \ =frac{1}{3} cdot6+75=2+75=77$

$sqrt{20.25} + sqrt[3]{24} - sqrt[4]{0.1296} - frac{2}{5} sqrt[3]{375} + frac{1}{3} sqrt[5]{7 frac{19}{32} } = \ =sqrt{4.5^2} + sqrt[3]{8cdot3} - sqrt[4]{0.6^4} - frac{2}{5} sqrt[3]{125cdot3} + frac{1}{3} sqrt[5]{frac{243}{32} } = \ = 4.5 + 2sqrt[3]{3} -0.6 - frac{2}{5}cdot5 sqrt[3]{3} + frac{1}{3} sqrt[5]{(frac{3}{2})^5 } \ =3.9 + 2sqrt[3]{3} - 2 sqrt[3]{3} + frac{1}{3}cdotfrac{3}{2}= 3.9 + frac{1}{2} =3.9+0.5=4.4$