Question

Найдите значение дроби 
1) x²-8x-33/10x+30 при x = -9;12;111

Answer 1

$frac{x^2-8x-33}{10x+30} = frac{x(x-8)-33}{10(x+3)}$
при x=-9 : $frac{-9(-9-8)-33}{10(-9+3)} = frac{120}{60} =2$
при x=12 $frac{12(12-8)-33}{10(12+3)} = frac{15}{150} =0.1$
при x=111 :$frac{111(111-8)-33}{10(111+3)} = frac{11400}{1140} =10$

Answer 2

спасибо

Answer 3

а 2 сможешь?