Question

X^4-16x^2=0 решите плииииз

Answer 1

$x^{2} ( x^{2} -16)=0 \ x^{2} (x-4)(x+4)=0 \ x_1=0; \ x_2=4; \ x_3=-4.$

Answer 2

X^2(x^2-16)=0
X^2=0. X^2-16=0
X=0. X^2=16
X=4
X=-4