Question

2m-6 √2                     решите примеры на сокращение дробей
------------   =                
   2
m  -18

√2b+√10c
-----------------    =
b-5c



  2
n - 6m
------------           =
  2
n - n√24m+6m

Answer 1

$frac{2m-6 sqrt{2}}{m^2-18}=frac{2(m-3sqrt{2})}{m^2-( sqrt{18})^2}=frac{2(m-3sqrt{2})}{(m-sqrt{18})(m+sqrt{18})}=frac{2(m-3sqrt{2})}{(m-3sqrt{2})(m+3sqrt{2})}=frac{2}{m+3sqrt{2}}$
$frac{ sqrt{2b}+ sqrt{10c}}{b-5c}=frac{ sqrt{2}(sqrt{b}+ sqrt{5c})}{(sqrt{b}-sqrt{5c})(sqrt{b}+ sqrt{5c})}= frac{sqrt{2}}{sqrt{b}-sqrt{5c}}$
$frac{n^2-6m}{n^2-n sqrt{24m}+6m}=frac{(n-sqrt{6m})(n+sqrt{6m})}{n^2-2*n sqrt{6m}+(sqrt{6m})^2}= frac{(n-sqrt{6m})(n+sqrt{6m})}{(n-sqrt{6m})^2}= frac{n+sqrt{6m}}{n-sqrt{6m}}$