Question

Помогите срочно надо!
№1
x(x-3)(x-2)(x+1)=54

Answer 1

$x(x-3)(x-2)(x+1)=54\(x^2-3x)(x^2-x-2)=54\x^4-4x^3+x^2+6x=54\x^4-4x^3+x^2+6x-54=0\(x^2-2x+6)(x^2-2x-9)=0\begin{cases}x^2-2x+6=0;;-;;D<0,;pew.;HET\x^2-2x-9=0end{cases}\x^2-2x-9=0\D=4+4cdot9=40=left(2sqrt{10}right)^2\x_1=frac{2-2sqrt{10}}2=1-sqrt{10}\x_2=frac{2+2sqrt{10}}2=1+sqrt{10}$