Question

Решите вообще не могу понять тему,если можно с объяснениями А и Б

Answer 1

$(frac{x}{x+1}+frac{x^2+1}{1-x^2}-frac{x}{x-1}):frac{x+x^2}{(1-x)^2} = (frac{x}{x+1}-frac{x^2+1}{x^2-1}-frac{x}{x-1})cdotfrac{(1-x)^2}{x+x^2} = \ = (frac{x}{x+1}^{(x-1}-frac{x^2+1}{(x+1)(x-1)}-frac{x}{x-1}^{(x+1})cdotfrac{(x-1)^2}{x(1+x)} = \ = frac{x(x-1)-(x^2+1)-x(x+1)}{(x+1)(x-1)}cdotfrac{(x-1)^2}{x(x+1)}= frac{x(x-1-(x+1))-x^2-1}{x+1}cdotfrac{x-1}{x(x+1)} =\= frac{x(x-1-x-1)-x^2-1}{x+1}cdotfrac{x-1}{x(x+1)} = frac{-x^2-2x-1}{x+1}cdotfrac{x-1}{x(x+1)} =$
$frac{-(x^2+2x+1)(x-1)}{x(x+1)^2} = frac{-(x+1)^2(x-1)}{x(x+1)^2} = frac{1-x}{x}$
$frac{(a-5)^2}{a^2+5a}:(frac{5}{a+5} - frac{a^2+25}{a^2-25} - frac{5}{5-a}) = frac{(a-5)^2}{a(a+5)}:(frac{5}{a+5} - frac{a^2+25}{(a+5)(a-5)} + frac{5}{a-5}) = \ = frac{(a-5)^2}{a(a+5)}:frac{5(a-5)+(a^2+25)+5(a+5)}{(a+5)(a-5)} = frac{(a-5)^2}{a(a+5)}cdotfrac{(a+5)(a-5)}{5a-25-a^2-25+5a+25} = \ = frac{(a-5)^2}{a}cdotfrac{a-5}{-a^2+10a-25} = frac{(a-5)^3}{-a(a^2-10a+25)}=frac{(a-5)^3}{-a(a-5)^2}=frac{a-5}{-a}=frac{5-a}{a}.$

Answer 2

Какая прога где писал?