Question

b+3a/18a^2b+a-4b/24ab^2

Answer 1

$frac{b+3a}{18a^2b}+frac{a-4b}{24ab^2}=frac{4b(b+3a)+3a(a-4b)}{72a^2b^2} =frac{4b^2+12ab+3a^2-12ab}{72a^2b^2} =frac{4b^2+3a^2}{72a^2b^2}$