Question

помогите найти значение выражения 2-3sin^2x, если cos^2x=3/4

Answer 1

2-4sin^2, если cos^2 X=3/4
1+1-4sin^2 X = sin^2 x+cos^2 x+sin^2 x+ cos^2 X - 4sin^2 X = 2sin^2 X + 2cos^2 X - 4sin^2 X = 2cos^2 X - 2sin^2 X = 2 (cos^2 X - sin^2 X )= 2 (cos^2 X -1+cos^2 X )=2 (3/4 - 4/4 + 3/4) = 2 (6/4 - 4/4)= 2 × 2/4= 1