Question

Решите пожалуйста 1.151 задание а)

Answer 1

$frac{2a}{a+1}+( frac{3}{(a-1)^2}- frac{3}{(a-1)(a+1)}): frac{3}{(a-1)^2}=frac{2a}{a+1}+frac{3(a+1)-3(a-1)}{(a-1)^2(a+1)}: frac{3}{(a-1)^2}= \ =frac{2a}{a+1}+frac{3a+3-3a+3}{(a-1)^2(a+1)}: frac{3}{(a-1)^2}=frac{2a}{a+1}+frac{6}{(a-1)^2(a+1)}* frac{(a-1)^2}{3}=frac{2a}{a+1}+frac{2}{a+1} \ = frac{2a+2}{a+1}= frac{2(a+1)}{a+1}=2$