Question

Помогите с алгеброй 11 класс 
номер 7.19 (б,в,г)

Answer 1

$sqrt{ frac{x}{y}sqrt{frac{y}{x} sqrt[3]{ frac{x}{y}}}}cdot sqrt[3]{ frac{y}{x}}= sqrt{ frac{x}{y}sqrt{sqrt[3]{ frac{y^3x}{x^3y} }}}cdot sqrt[3]{frac{y}{x}}= sqrt{ frac{x}{y}sqrt[6]{frac{y^2}{x^2}}}cdotsqrt[3]{frac{y}{x}}= \ = sqrt{ frac{x}{y}sqrt[3]{ frac{y}{x} } } cdot sqrt[3]{ frac{y}{x}}= sqrt{sqrt[3]{ frac{x^3y}{y^3x}}}cdot sqrt[3]{ frac{y}{x}} = sqrt{sqrt[3]{ frac{x^2}{y^2}}}cdotsqrt[3]{frac{y}{x}}= sqrt[3]{ frac{xy}{yx}}=1$

$sqrt{x sqrt{x sqrt{x sqrt{x}}}}: sqrt[16]{x^{11}} = sqrt{sqrt{x^2xsqrt{x sqrt{x}}}}: sqrt[16]{x^{11}} = \ =sqrt[4]{x^3sqrt{x sqrt{x}}}}: sqrt[16]{x^{11}}= sqrt[4]{sqrt{x^6x sqrt{x}}}}: sqrt[16]{x^{11}}= sqrt[8]{x^7 sqrt{x}}}: sqrt[16]{x^{11}}= \ =sqrt[8]{sqrt{x^{14}x}}}: sqrt[16]{x^{11}}= sqrt[16]{x^{15}}: sqrt[16]{x^{11}}=sqrt[16]{x^{4}}=sqrt[4]{x}$

$sqrt{2msqrt[3]{frac{1}{4m^2}sqrt{frac{n}{m}}}}:sqrt[12]{mn}= sqrt{sqrt[3]{frac{8m^3}{4m^2}sqrt{frac{n}{m}}}}:sqrt[12]{mn}= \ =sqrt[6]{2msqrt{frac{n}{m}}}:sqrt[12]{mn}= sqrt[6]{sqrt{frac{4m^2n}{m}}}:sqrt[12]{mn}= \ =sqrt[12]{4mn}:sqrt[12]{mn}=sqrt[12]{4}=sqrt[6]{2}$

Answer 2

спс