Question

20sin135°×cos45° помогите

Answer 1

$20*sin135^0*cos45^0=$

$=10*sin(90^0+45^0)*sqrt{2}=10*(sin90^0cos45^0+sin45^0cos90^0)sqrt{2}=$

$=10*(1*frac{sqrt{2}}{2}+0*frac{sqrt{2}}{2})sqrt{2}=10*frac{sqrt{2}}{2}*sqrt{2}=10$

Ответ: 10.