Question

логарифмические уравнения. срочноооооо!!!!!!!!'

Answer 1

1) $log_{ frac{1}{2}}(3-4x) = -3$ <=> 5-2x = $frac{1}{2} ^{-3} = 2^{3} = 8$
5-8 = 2x <=> -3 = 2x <=> x = -3/2 = -1.5
2) $log_{0.5} (3+4x)$=-2 <=> 3+4x = 0.5^(-2) = (1/2)^-2 = 4
=> 3-4x= 4 <=> 3-4 = 4x <=> -1 = -4x => x=-1/4 = -0.25