Question

Задача:

Дано:

ню(CxHy)=1моль

m(CO2)=22,4л

m(H2O)=36г

v(O2)=5л

найти:CxHy 

Answer 1

                                     1               1          2

                                    СxHy+O2=CO2+2H2O       - з-н объемных отношений

                                    CxHy+2O2=CO2+2H2O

                                     ответ:СН4-метан.

.....................................................