Question

Решите уравнение:4x^3-4x=0

Answer 1

4x³ - 4x = 0
4x·(x² - 1) = 0
4x·(x - 1)·(x + 1) = 0

x₁ = -1
x₂ = 0
x₃ = 1

Answer 2

$x(4x^2-4)=0\x_1=0;4x_2^2=4\x_1=0;x_2^2=1\x_1=0;x_2=1;x_3=-1$