Question

найти корни:
x^{1.5} [/tex]=27
$( frac{1}{sqrt{5} } ) ^{ sqrt{x} } = frac{1}{25}$

Answer 1

$x^{1,5}=27\\x^{ frac{3}{2} }=27\\ sqrt{x^3} =27\\x^3=27^2\\x= sqrt[3]{3^6}\ \x=3^2\x=9$


$( frac{1}{sqrt{5} } ) ^{ sqrt{x} } = frac{1}{25} \\( frac{1}{5 } ) ^{ frac{sqrt{x}}{2} } = (frac{1}{5} )^2\\frac{sqrt{x}}{2}=2\\ sqrt{x} =4\\x=16$

Answer 2

1.  x^1,5 = 27;
 x^1,5 = 3^3;
x^1,5 = 3^(2*1,5);
x^1,5 = 9^1,5;
x = 9.
2. (5^(-1/2)^x^1/2 = 5^ -2;
(5^(- x/2)^1/2)= 5^-2;
 (5)^(- x/4) = 5^ -2;
 - x/4 = -2;
- x = - 8;
 x = 8.