Question

Решите неравенство, пожалуйста

Answer 1

$frac{x^2-4,5x-3}{5-2,5x} leq 1, \ 5-2,5x neq 0, -2,5x neq -5, x neq 2, \ frac{x^2-4,5x-3}{5-2,5x}-1 leq 0, \ frac{x^2-4,5x-3-(5-2,5x)}{5-2,5x} leq 0, \ frac{x^2-4,5x-3-5+2,5x}{5-2,5x} leq 0, \ frac{x^2-2x-8}{5-2,5x} leq 0, \ frac{x^2-2x-8}{5-2,5x} = 0, \ x^2-2x-8=0, \ x_1=-2, x_2=4, \ x^2-2x-8=(x+2)(x-4), \ (x+2)(x-4)(5-2,5x) leq 0, \ -2,5(x+2)(x-4)(x-2) leq 0, \ (x+2)(x-2)(x-4) geq 0, \ xin [-2;2)cup[4;+infty)$