Question

Помогите решить, 1,2,3

Answer 1

$1.;a);(17,2cdot4,01+4,01cdot32,8):1frac23=left(4,01cdot(17,2+32,8)right):frac53=\=(4,01cdot50)cdotfrac35=4,01cdot50cdotfrac35=4,01cdot10cdot3=40,1cdot3=120,3\b);frac12-left(frac12right)^2cdot2frac23-25cdot0,03cdot4=frac12-frac14cdotfrac83-25cdot4cdotfrac3{100}=\=frac12-frac23-100cdotfrac3{100}=-frac16-3=-3frac16$

$2.;3(2y-x)-2(y-3x)=6y-3x-2y+6x=3x+4y\3cdotleft(-frac29right)+4cdot0,25=-frac23+1=frac13$

$3.;10a+5b$