Question

Mr(H3 POh)=
Mr(H2 CO3)=
Mr(KMn O4)=

Answer 1

$M _{r} (H _{3} P O_{4} )=1*3+31+16*4=3+31+64=98$
$M_{r}(H_{2}CO_{3})=1*2+12+16*3=2+12+48=62$
$M_{r}(KMnO_{4})=39+55+16*4=39+55+64=158$