Question

(2x-3)(2x+3)-1=5x+(x-2) в квадрате

Answer 1

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Answer 2

(2x-3)(2x+3)-1=5x+(x-2)^2

4x^2 - 9 - 1 = 5x + x^2 - 4x + 4
3x^2 -14 - x = 0
 3x^2 - x -14 

 D = b^2 -4ac = 1 + 168 = 169
x1 = (-b +  корень из D) / 2a = 7/3

x2 = (-b -  корень из D) / 2a = -2