Question

6.14(а) 6.15(а,б)

Срочно решите плз

Answer 1

6.14 a) $5ab^{-3}+3a^{-2}b^2-2a^{-4}=a^{-4}(5b^{-3}a^{1-(-4)}+3b^2a^{-2-(-4)}-2a^{-4-(-4)}$ = $a^{-4}(5a^5b^{-3}+3a^2b^2-2)$
6.15 a) $5a^{k-2}+3a^{k+2}+23a^{k-5}$ = $a^{k-5}(5a^{k-2-k+5}+3a^{k+2-k+5}+23a^{k-5-k+5}=a^{k-5}(5a^3+3a^7+23)$
b) $3a^{3-d}-5a^{2-d}-5a^{5-d}=a^{2-d}(3a^{3-d-2+d}-5a^{2-d-2+d}-5a^{5-d-2+d})$ = $a^{2-d}(3a-5-5a^3)$