Question

Сократите дробь:

a)75b^5c^3/50b^4c^4
б)2b/b^2-8b
в)7x-7y/x^2-y^2
г)a^2-36/a^2-12a+36

Answer 1

$frac{75b^5c^3}{50b^4c^4} =frac{3*5*5*b^5c^3}{2*5*5*b^4c^4} =frac{3b}{2c}$


$frac{2b}{b^2-8b} = frac{2b}{b(b-8)} =frac{2}{b-8}$


$frac{7x-7y}{x^2-y^2} =frac{7(x-y)}{(x-y)(x+y)} =frac{7}{x+y}$


$frac{a^2-36}{a^2-12a+36}= frac{(a-6)(a+6)}{(a-6)^2} =frac{a+6}{a-6}$