Question

Упростить 8 класс.............

Answer 1

$frac{a^2}{3a-18}+frac{3b}{-(3a-18)}=frac{a^2}{3a-18}-frac{3b}{3a-18}=frac{a^2-3b}{3a-18}=frac{a^2-3b}{3 cdot (a-6)}$


$...=frac{5b+3-(6b-1)}{b^2 -16}=frac{5b+3-6b+1}{(b-4) cdot (b+4)}=frac{-b+4}{(b-4) cdot (b+4)}=-frac{b-4}{(b-4) cdot (b+4)}=-frac{1}{b+4}\ \ \ -frac{1}{b+4}=-frac{1}{-3+4}=-frac{1}{1}=-1$