Question

Домашнее задание (1,2)

Answer 1

$lim_{xto infty}frac{3x^5+2x^7}{2x^5-8x^7}=[delim; na; x^7]=lim_{xto infty}frac{frac{3}{x^2}+2}{frac{2}{x^2}-8}=\\=[frac{3}{x^2}to 0,frac{2}{x^2}to 0]=-frac{2}{8}=-frac{1}{4}\\\lim_{xto infty}frac{4x^5-3x+2}{3+2x^3+5x^5}=[delim; na; x^5]=lim_{xto infty}frac{4-frac{3}{x^4}+frac{2}{x^5}}{frac{3}{x^5}+frac{2}{x^2}+5}=frac{4}{5}$