Question

(x^2-6x)^2+2(x-3)^2=8

Answer 1

$(x^2-6x)^2+2(x-3)^2=8\\(x^2-6x)^2+2(x^2-6x+9)=8\\(x^2-6x)^2+2(x^2-6x)+10=0\\t:=x^2-6x\\t^2+2t+10=0\D<0$

вещественных корней нет