Question

|x^2-4x|=5
|x^2-1|+x=5
_________
^2 - квадратный корень.
Помогите с решением пожалуйста

Answer 1

$|x^2-4x|=5, \ left [ {{x^2-4x=5,} atop {x^2-4x=-5;}} right. left [ {{x^2-4x-5=0,} atop {x^2-4x+5=0;}} right. left [ {{ left [ {{x=-1,} atop {x=5,}} right. } atop {xinvarnothing; (D=-4<0)}} right. left [ {{x=-1,} atop {x=5.}} right.$

$|x^2-1|+x=5, |x^2-1|=5-x, \ 5-xgeq0, -xgeq-5, xleq5;\ left [ {{x^2-1=5-x,} atop {x^2-1=x-5;}} right. left [ {{x^2+x-6=0,} atop {x^2-x+4=0;}} right. left [ {{ left [ {{x=-3,} atop {x=2,}} right. } atop {xinvarnothing; (D=-15<0)}} right. left [ {{x=-3,} atop {x=2.}} right.$