Question

Помогите решить!!
-3х2+17х+6<0

Answer 1

-3x²+17x+6 <0
3x²-17x-6 <0
D=(-17)²-4*3*(-6)=289+72=361=19²
x1=(17+19)/2*3=36/6=6
x2=(17-19)/2*3=-2/6=-1/3
3(x-6)(x+1/3)<0
                +                               -                                  +
______________-1/3__________________6______________

x∈(-1/3; 6)