Question

2 sin^2(-п/6)+cos^2(-п/3)/2 cos(-п/3)+sin(-п/6)

Answer 1

sin (-П/6) = -1/2; cos (-П/3) = 1/2

2sin^2 (-П/6) + cos^2 (-П/3)/2*cos (-П/3) + sin(-П/6) =

= 2*(-1/2)^2 + (1/2)^2/2*(1/2) + (-1/2) = 2/4 + 1/4*1/4 - 1/2 = 1/16