Question

Решите номер 38.Есть вложение.

Answer 1

$cfrac{1}{1- cfrac{1}{1+ frac{1}{x} } } = cfrac{1}{1- cfrac{1}{frac{x+1}{x} } } = cfrac{1}{1- frac{x}{x+1} } = cfrac{1}{ frac{x+1-x}{x+1} } = cfrac{1}{ frac{1}{x+1} } =x+1$

$cfrac{1}{1- cfrac{1}{1- frac{1}{1+a} } } = cfrac{1}{1- cfrac{1}{ frac{1+a-1}{1+a} } } = cfrac{1}{1- cfrac{1}{ frac{a}{1+a} } } = cfrac{1}{1- frac{1+a}{a} } =cfrac{1}{ frac{a-1-a}{a} } =cfrac{1}{ frac{-1}{a} } =-a$