Question

Решите номер 36.Есть вложение.

Answer 1

$cfrac{a- frac{4a-4}{a} }{ frac{2}{a}-1 } = cfrac{frac{a^2-4a+4}{a} }{ frac{2-a}{a} } = frac{(a-2)^2a}{a(2-a)} =2-a$

$cfrac{1- frac{3}{c} }{ frac{6c-9}{c}-c } = cfrac{ frac{c-3}{c} }{ frac{6c-9-c^2}{c} } = frac{(c-3)c}{c(6c-9-c^2)} =- frac{(c-3)}{(c-3)^2} =- frac{1}{c-3} = frac{1}{3-c}$