Question

$2^{log_{4}9} - log_{2}6$

Answer 1

$2^{log_{4}9}-log_{2}6=2^{log_{4}3^{2}}-log_{2}6=2^{2log_{4}3}-log_{2}6=\\=4^{log_{4}3}-log_{2}6=3-log_26=log_28-log_26=log_2(frac{8}{6})=log_2(frac{4}{3}).$