Предмет: Алгебра, автор: arafat256

стороны первого прямоугольника равны 4 см и 6 см, а стороны второго 8 см и 15 см во сколько раз площадь второго прямоугольника больше площади первого прямоугольника

Ответы

Автор ответа: lexamil

4•6=24см площадь первого прямоугольника
15•8=120см площадь второго
120:24=5 раз площадь первого прямоугольника больше площади второго

Автор ответа: nik237801

s=a*b
s1=4*6=24
s2=8*15=120
120:24=5
Ответ: в 5 раз

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