Question

найти 
sin a;cos a ; tg a ;ctg a
1]cos a =-2/3
2]sin a =1/4

Answer 1

1. sin α = √(1-cos²α) = √(1- 49) = √(59)= √5 3
tg α = sin α cos α = √53 : (-23) = -√52
ctg α = 1 tg α = 1 (-√52) = -2 √5 = -2√5 5
2. cos α = √(1-sin²α) = √(1-116) = √(1516) = √15 4
tg α = 14 : √154 = 1√15 = √15 15
ctg α = 1  1√15 = √15