Question

найдите корни уровн 2х^2+11х+34=(х+6)^2

Answer 1

2x^2+11x+34=(x+6)^2
2x^2+11x+34=x^2+12x+36
2x^2-x^2+11x-12x+34-36=0
x^2-x-2=0
D=b^2-4ac=(-1)^2-4*1*(-2)=9
x1=(-b+√D)/2*a=(1+3)/2=2
x2=(-b-√D)/2a=(1-3)/2=-1