Question

массовая доля каждого вещества в H3PO4

Answer 1

1. Молекулярная масса Н3РО4 = 98 гр/моль

W(H)=(3*1)/98=3.06%

W(P)=31/98=31.63%

W(O)=(4*16)/98=65.3%

Answer 2

M(H3PO4) = 1*3 + 31 + 16*4 = 3 + 31 + 64 = 98 г/моль

W(H) = (3/98)*100% = 3%

W(P) = (31/98)*100% = 31.7%

W(O) = 100 - 3.06 - 31.6 = 65.3%