Question

Привести к стандартному виду многочлен:
2ab^2-11a^3-3ba^2+5ab^2+7a^2b+4a(-1)ba-(a+b)ab

Answer 1

  2ab^2-11a^3-3ba^2+5ab^2+7a^2b+4a(-1)ba-(a+b)ab=
=2ab^2-11a^3-3a^2b+5ab^2+7a^2b-4a^2b-a^2b-ab^2=
=-11a^3-a^2b+6ab^2=a(-11a^2-ab+6b^2)