Question

1)х*(х²+9)*(х-4)=0
2)5х-(3х+2)=7х-5(2х+1)

Answer 1

$x(x+9)(x-4)=0 \ x(x+3)(x-3)(x-4)=0 \ x=0 \ x=-3 \ x=3 \ 5x-(3x+2)=7x-5(2x+1) \ 5x-3x-2-7x+10x+5=0 \ 12x=-3 \ x=-0.25$