Question

$frac{2x}{x-1}+frac{3x+1}{1-x^2}-frac{3}{x+1}$

Answer 1

$=frac{-2x(x+1)+3x+1-3(1-x)}{1-x^2}=frac{-2x^2-2x+3x+1-3+3x}{1-x^2}=frac{-2x^2+4x-2}{1-x^2}=$

 

$=frac{-2(x^2-2x+1)}{1-x^2}=frac{2(x-1)^2}{x^2-1}=frac{2(x-1)^2}{(x+1)(x-1)}=frac{2(x-1)}{x+1}$