Question

решите неравенства: (12х-1)(3х+1) меньше 1+(6х+2)2

Answer 1

$(12x - 1)(3x + 1) < 1 + (6x + 2)^2 \ 36x^2 + 9x - 1 < 1 + 36x^2 + 24x + 4 \ 33x > -6 \ x >- frac{6}{33} \ x > - frac{2}{11}$