Question

Корень 3 sin 6 x - 3 cos 6 x = 0

Answer 1

$sqrt{3} sin6x-3cos6x=0|:cos6x \ sqrt{3} tg6x-3=0 \ tg6x= frac{3}{ sqrt{3} } \ 6x=arctg( frac{3}{ sqrt{3} } )+ pi n,nin Z \ 6x= frac{ pi }{3} + pi n,n in Z \ x= frac{ pi }{18} + frac{ pi n}{6} ,n in Z$