Question

(3х+2у)в квадрате минус (2х+3у)в квадрате=

Answer 1

$(3x+2y)^{2} - (2x+3y)^{2} = 9x^{2} +12xy+ 4y^{2} -( 4x^{2} +12xy+ 9y^{2} )=$
$= 9x^{2} +12xy+ 4y^{2} - 4x^{2} -12xy- 9y^{2} = 5x^{2} - 5y^{2} =5( x^{2} - y^{2} )$