Question

8х (1+2х)-(4х+3)*(4х-3)=2х ???

Answer 1

$8x*(1+2x)-(4x+3)*(4x-3)=2x \ 8x+16x^2-(16x^2-9)=2x \ 8x+16x^2-16x^2+9=2x \ 8x-2x=-9 \ 6x=-9 \ x=- frac{9}{6} \ \ x= frac{3}{2} \ \ x=-1 frac{1}{2} \ \ x=-1,5$
Ответ: $x=-1.5$

Answer 2

хорошо