Question

решите уравнение log1/2(2x-1)-log1/2(16)=5

Answer 1

log1/2(2x-1)-log1/2(16)=5          ОДЗ:2x-1> 0

log1/2 (2x-1)/16 =5                           2x > 1

(2x-1)/16 = (1/2)^5                           x > 0,5

(2x-1)/16 =1/32

2x-1=0,5

2x=1,5

x=7,5