Question

помогите!!!!!!!!!!!!!!

Answer 1

1)y=$-x^5+2x^3-3x^2-1$
y`=$-5x^4+6x^2-6x$
2)y=$2/x^3 -8 sqrt[4]{x}$
y`=$-6/x^4-2/ sqrt[4]{x^3}$
3)y=$(4-3x)^7$
y`=$-21(4-3x)^6$
4)y=$1/ sqrt{1-2x}$
y`=$-2/ sqrt{(1-2x)^3}$
5)y=cos1/2x-sin(x/2 + 5)=-1/2sin1/2x -1/2cos(x/2 +5)

Answer 2

$1); y=-x^5+2x^3-3x^2-1\\y'=-5x^4+6x^2-6x\\2); y=frac{2}{x^3}-8sqrt[4]{x}=2x^{-3}-8x^{frac{1}{4}}\\y'=2cdot (-3)x^{-4}-8cdot frac{1}{4}x^{-frac{3}{4}}\\3); y=(4-3x)^4\\y'=4(4-3x)^3cdot (-3)\\4); y=frac{1}{sqrt{1-2x}}=(1-2x)^{-frac{1}{2}}\\y'=-frac{1}{2}(1-2x)^{-frac{3}{2}}(-2)=(1-2x)^{-frac{3}{2}}$

$5); y=cos(frac{1}{2}x)-sin(frac{x}{2}+5)\\y'=-sin(frac{1}{2}x)cdot frac{1}{2}-cos(frac{x}{2}+5)cdot frac{1}{2}=-frac{1}{2}(sinfrac{x}{2}+cos(frac{x}{2}+5))$