Question

x+y=34,  xy= 2целых 58 .Найдиите x^2+y^2

Answer 1

$x+y=frac{3}{4},; ; xy=2frac{5}{8}=frac{21}{8}\\(x+y)^2=x^2+y^2+2xy\\(frac{3}{4})^2=x^2+y^2+2cdot frac{21}{8}\\x^2+y^2=-frac{9}{16}+frac{21}{4}=frac{-9+21cdot 4}{16}=frac{75}{16}=4,6875$