Question

Сократить
a$frac{a^{2}-b^{2} -c^{2} +2bc }{b^{2}-c^{2}-a^{2}-2ac}$

Answer 1

(a²-b²-c²+2bc)/(b²-c²-a²-2ac)=[(a²-(b²+c²-2bc)]/[b²-(c²+a²+2ac)]=
=[(a²-(b-c)²]/[b²-(a+c)²]=(a-b+c)(a+b-c)/(b-a-c)(b+a+c)=-(a+b-c)/(b+a+c)=
=(c-a-b)/(b+a+c)