Question

6а^2+11а+3/3+5а-12а^2

Answer 1

6а^2+11а+3/3+5а-12а^2 =
6(х+3/4)(х+3/2)/2(х+1/3)(х+3/4)= (х+3/2)/-2(х+1/3)


6а^2+11а+3=0 Д=121-72=49
х1=(-11+7)/12=-4/12=-3/4
х2=(-11-7)/12=-18/12=-3/2
3+5а-12а^2=0  Д=25+144=169
х1=(-5+13)/-24=-8/24=-1/3
х2=(-5-13)/-24=-18/-24=-3/4