Question

Решите систему уравнений:
 3x-y=10
x^2-y^2=20-xy

Answer 1

$left { {{3x-y=10} atop {x^2-y^2=20-xy}} right. to left { {{y=3x-10} atop {x^2-y^2=20-xy}} right. \ \ left { {{y=3x-10} atop {x^2-(3x-10)^2=20-x(3x-10)}} right. \ \ x^2-6x^2+60x-100-20+3x^2-10x=0 \ x^2-10x+24=0 \ \ x_1=4 \ x_2=6 \ \ y_1=2 \ y_2=8 \ \ OTBET:(4;2),(6;8)$