Question

Разложите на множители
12a^2b^2+6a^2b^3+12ab^3
b(b-2)^2+b^2(2-b)
ax-5x-a^2+5A
ab-ac+2c-2b-b+c

Answer 1

12a²b²+6a²b³+12ab³=6ab²(2a+ab+2b)
b(b-2)²+b²(2-b)=b(b-2)-b²(b-2)=b(b-2)(1-b)
ax-5x-a²+5a=(ax-5x)-(a²-5a)=x(a-5)-a(a-5)=(a-5)(x-a)
ab-ac+2c-2b-b+c=ab-ac+3c-3b=a(b-c)-3(b-c)=(b-c)(a-3)