Question

(2у-3х)2-(3х+2у)(2у-3х) после скобки 2 степень

Answer 1

(2y - 3x)^2 - (2y + 3x)( 2y - 3x) = 
= 4y^2 - 12xy + 9x^2 - (4y^2 - 9x^2) = 
= 4y^2 - 12xy + 9x^2 - 4y^2 + 9x^2 = 
= 18x^2 - 12xy = 
= 6x*(3x - 2y)

Answer 2

$(2y-3x)^{2} -(3x+2y)(2y-3x)=4y^{2} +9 x^{2} -12xy-(4y^{2} -9 x^{2} )= \ =4y^{2} +9 x^{2} -12xy-4y^{2} +9 x^{2} =18 x^{2} -12xy=6x(3x-2y)$